HomeChemistry ToolsMole Ratio Calculator with Steps (Molar Ratio) | StatsUnlock

Mole Ratio Calculator with Steps (Molar Ratio) | StatsUnlock

Mole Ratio Calculator

Find every mole ratio in a chemical equation and convert moles of one substance to moles or grams of another, calculate an experimental mole ratio from lab masses, the molar ratio of two compounds from their molecular weights, or the insert : vector molar ratio for DNA cloning. Every step shown, with a figure and four charts.

ChemistryMole RatioStoichiometryExperimental RatioDNA CloningFree

⚡ 0. Quick Answer

To calculate a mole ratio, balance the equation and read the coefficients: in N2 + 3H2 → 2NH3 the mole ratio of N2 : H2 : NH3 is 1 : 3 : 2. To convert, multiply the moles you have by (coefficient wanted ÷ coefficient given):

6.00 mol H2 × (2 mol NH3 ÷ 3 mol H2) = 4.00 mol NH3 = 68.1 g

Rule of thumb: mole ratios come from coefficients, never from subscripts or masses. For an experimental mole ratio, convert each mass to moles and divide by the smallest: 1.27 g Cu and 4.32 g Ag give 0.01999 : 0.04005 = 1 : 2.00. For DNA cloning, insert ng = vector ng × (insert bp ÷ vector bp) × ratio, so 50 ng of a 3000 bp vector needs 50.0 ng of a 1000 bp insert at 3 : 1.

🔑 Key Takeaways

  • A mole ratio is the ratio of the coefficients of two substances in a balanced equation; it is a conversion factor between their moles.
  • An equation with n substances has n(n − 1) ÷ 2 mole ratios: propane combustion, C3H8 + 5O2 → 3CO2 + 4H2O, has 6.
  • Mole ratios work in moles: convert grams with the molar mass first. 44.1 g of propane is 1.000 mol, which needs 5.00 mol O2.
  • An experimental mole ratio divides measured moles by the smallest and rounds; values near .5 or .33 are multiplied by 2 or 3 (Fe : O = 1 : 1.50 becomes 2 : 3).
  • A DNA molar ratio counts molecules, not nanograms: a 3 : 1 insert : vector ratio with a 1000 bp insert and 50 ng of a 3000 bp vector is 50.0 ng of insert.

📚 1. What Is a Mole Ratio, and How Does a Mole Ratio Calculator Work?

A mole ratio (also called a molar ratio or mole-to-mole ratio) is the ratio between the amounts, in moles, of two substances in a reaction. It comes from the coefficients of the balanced chemical equation: N2 + 3H2 → 2NH3 says that 1 mol of nitrogen reacts with 3 mol of hydrogen to give 2 mol of ammonia, whatever the scale. That is why mole ratios are central to every stoichiometric calculation: they are the only bridge between one substance and another.

A mole ratio calculator balances the equation for you, lists all possible mole ratios, and converts an amount of one substance (in moles, grams, mL of solution, litres of gas or particles) into the moles and grams of every other substance. It can also work backwards from the lab: from measured masses to an experimental mole ratio, or from two masses and molecular weights to the molar ratio of two compounds. For molecular biology it gives the insert : vector molar ratio used in ligation, In-Fusion and Gibson or NEBuilder assembly.

A worked one-liner: how many moles of oxygen react with 5.0 mol of hydrogen? 2H2 + O2 → 2H2O gives O2 : H2 = 1 : 2, so 5.0 × 1/2 = 2.5 mol O2.

One N2 and three H2 make two NH3: the coefficients 1, 3 and 2 are the mole ratios Coefficients are the mole ratio: 1 : 3 : 2 1 N₂ + 3 H₂ 2 NH₃ 2.00 mol6.00 mol (given)4.00 mol 6.00 mol H₂ × 2/3 = 4.00 mol NH₃; 6.00 mol H₂ × 1/3 = 2.00 mol N₂
One circle is one mole per reaction. Scaling the whole reaction to 6.00 mol of H2 keeps the 1 : 3 : 2 ratio.

Who uses it: mole ratios are taught in NCERT Class 11 (“Some Basic Concepts of Chemistry”), GCSE, A level, AP Chemistry and IB, and asked in JEE, NEET and the MCAT. Lab students use experimental mole ratios to identify a reaction or a hydrate; molecular biologists set up ligations with an insert : vector molar ratio every week.

Balanced equationMole ratioExample conversion
N2 + 3H2 → 2NH31 : 3 : 26.00 mol H2 → 4.00 mol NH3
2H2 + O2 → 2H2O2 : 1 : 25.0 mol H2 → 2.5 mol O2
C3H8 + 5O2 → 3CO2 + 4H2O1 : 5 : 3 : 41.000 mol C3H8 → 3.00 mol CO2
Fe2O3 + 3CO → 2Fe + 3CO21 : 3 : 2 : 32.50 mol Fe2O3 → 5.00 mol Fe
HCl + NaOH → NaCl + H2O1 : 1 : 1 : 125.0 mL of 0.100 M NaOH → 0.00250 mol HCl

What this free mole ratio calculator solves

One tool covers every mole ratio calculation in a chemistry course and a cloning lab: a mole to mole ratio calculator, an all possible mole ratios calculator, a stoichiometry mole ratio calculator, a molar ratio calculator for two compounds from molecular weight, an experimental mole ratio calculator, and a DNA molar ratio calculator for ligation and In-Fusion cloning. Press Try it to load an example, then press the button to see the working.

ProblemWhat it works outExample
Mole-to-mole conversionMoles and grams of the substance you want6.00 mol H2 → 4.00 mol NH3
All possible mole ratiosEvery pair from the balanced equationPropane: 6 ratios
From gramsMass ÷ molar mass, then every ratio44.1 g C3H8 → 5.00 mol O2
Experimental mole ratioMoles, ratio ÷ smallest, whole numbers, % differenceCu : Ag = 1 : 2.00
Hydrate formulaWater to salt mole ratioCuSO4 · 5H2O
Molar ratio of two compoundsFrom masses and molar masses10.0 g NaCl : 10.0 g KCl = 1.28 : 1
From molecular weightMass needed for a target molar ratio1 : 2 glucose : sucrose
DNA ligation molar ratioInsert ng and fmol for 3 : 150 ng vector → 50.0 ng insert
In-Fusion molar ratio2 : 1 for each insert, with volumesTwo inserts: 60.0 and 32.0 ng

Free, with no sign-up. Everything runs in your browser: nothing you type is sent to a server or stored.

En español: ¿cómo se calcula la relación molar? Balancea la ecuación y usa los coeficientes: en N2 + 3H2 → 2NH3, 6,00 mol de H2 × 2/3 = 4,00 mol de NH3.

How accurate is this mole ratio calculator?

Equations are balanced exactly with whole-number coefficients, and molar masses use the CIAAW 2024 standard atomic weights (Prohaska et al., 2022). Answers are given to the number of significant figures in your data. Every answer is checked before it gets the Verified badge: the equation must conserve mass, and every amount divided by its coefficient must give the same extent of reaction. For DNA, molecular weights use 617.96 g/mol per base pair plus 36.04 g/mol, the average for double-stranded DNA used by vendor calculators. The R and Python scripts in Sections 10 and 11 return the same 4.00 mol NH3 and 1 : 2 Cu : Ag ratio as the headline problems.

Research on stoichiometry finds that most student errors come from using the mole ratio the wrong way up or from using masses in place of moles, not from the arithmetic (Schmidt & Jignéus, 2003; Gulacar et al., 2013). That is why the steps always show the ratio as a fraction with its units.

🧮 2. Enter Your Problem in the Mole Ratio Calculator

1. What do you have?

2. Equation (balanced or not)

Use -> for the arrow; the equation is balanced for you. Leave the amount empty to see only the mole ratios.

Press Enter in any box to calculate. Nothing is calculated until you press the button.

📊 3. Your Results: Mole Ratio Calculator with Steps

Mole ratio: ___ . Enter or load a problem above, then press Calculate Mole Ratio. The ratios, the converted amounts, the steps, a figure and four charts will appear here.

🧠 4. What Does Your Mole Ratio Mean?

Solve a problem above to fill this box with your own numbers: ___ . The sub-sections below explain every part of the output.

4.1 Why are mole ratios central to stoichiometric calculations?

A balanced equation describes the reaction in particles: one N2 molecule with three H2 molecules gives two NH3. A mole is a fixed number of particles (6.022 × 1023), so the same 1 : 3 : 2 ratio holds for moles. That makes the mole ratio the only link between two substances: grams, litres, molarity and particles must all be turned into moles, passed through the mole ratio, and turned back. Explaining the significance of the mole ratio in stoichiometric calculations comes down to this: without it you cannot get from what you have to what you want. A mole ratio calculator simply makes that bridge visible for every pair of substances at once.

4.2 How are mole ratios used in chemical calculations?

Write the ratio as a fraction with the substance you want on top and the one you have on the bottom, so the units cancel: 6.00 mol H2 × (2 mol NH3 ÷ 3 mol H2) = 4.00 mol NH3. The full road map is grams → moles (÷ M) → moles of the other substance (× mole ratio) → grams (× M). The mole ratio is also how you find the limiting reagent: divide the moles of each reactant by its coefficient, and the smallest runs out first.

4.3 Is a mole ratio the same as a mass ratio?

Mole ratios are not mass ratios. In N2 + 3H2 → 2NH3, the mole ratio N2 : H2 is 1 : 3, but the mass ratio is 28.014 : 6.048, about 4.6 : 1. Equal masses of NaCl and KCl contain different numbers of moles (0.171 and 0.134 mol in 10.0 g), so their molar ratio is 1.28 : 1, not 1 : 1. The mole ratio calculator always shows both, so the difference is clear.

4.4 What is an experimental mole ratio?

An experimental mole ratio is measured, not read from an equation. Divide each amount of moles by the smallest, then round. A value close to .5, .33 or .25 is a signal to multiply all the numbers by 2, 3 or 4 before rounding. In the mole ratio calculator, type the expected ratio to get the percent difference; comparing the two tells you how well the experiment went:

Difference from the expected ratioTypical descriptionCommon reason
Within 5%Good agreementCareful weighing, complete reaction
5 to 15%FairProduct lost in transfer, not fully dry
Above 15%PoorIncomplete reaction, side reaction, wet product, wrong equation

4.5 Hydrates and formulas

The same arithmetic gives the water of crystallisation of a hydrate: 1.60 g of anhydrous CuSO4 and 0.90 g of water driven off give 0.01002 : 0.0500 = 1 : 4.98, so the formula is CuSO4·5H2O. The experimental mode of the mole ratio calculator does this rounding for you. An empirical formula is an experimental mole ratio of atoms: 2.00 g Fe and 0.860 g O give 1 : 1.50 = 2 : 3, so Fe2O3.

4.6 What molar ratio should you use for DNA cloning?

In ligation and assembly reactions, what matters is the number of DNA molecules, so the ratio is a molar ratio. Because a 1000 bp insert has a third of the mass per molecule of a 3000 bp vector, a 3 : 1 insert : vector molar ratio needs equal masses: 50 ng of each. Common starting points are 3 : 1 for T4 DNA ligase, 2 : 1 for In-Fusion (Takara) and NEBuilder HiFi assembly, and 3–5 : 1 or more for fragments under about 350 bp; vendors stress that these are starting points to optimise. The DNA mode of the mole ratio calculator has buttons for each of these presets.

4.7 Whole-number and fractional ratios

Mole ratios from an equation are usually given as the smallest whole numbers, but fractions are just as correct for calculations: H2 : O2 = 2 : 1 is the same as 1 : 0.5. The mole ratio calculator gives each ratio both ways, so you can use whichever fraction makes the units cancel.

4.8 A field note on where mole ratio problems go wrong

Marking stoichiometry, the same slips come up: using an unbalanced equation, reading the ratio from subscripts (the 2 in H2) instead of coefficients, putting the ratio upside down, multiplying grams by the mole ratio, and rounding an experimental 1 : 1.5 to 1 : 2 instead of doubling it to 2 : 3. Writing units on every number stops most of them (Dori & Hameiri, 2003).

✍ 5. How to Write a Mole Ratio Answer

▶ Solve a problem above to fill all five cards with your own answer.

1. Exam answer with working
mol given × (coefficient wanted ÷ coefficient given) = ___ mol
📌 Conventions examiners look for
  • Write the balanced equation first.
  • Show the mole ratio as a fraction with units, so the units visibly cancel.
  • Convert grams to moles before using the ratio.
2. Final answer only
___
📌 Conventions
  • Give the unit and the substance: 4.00 mol NH3.
  • Round to the least number of significant figures in the data.
3. Lab report sentence
The mole ratio of ___ to ___ is ___.
📌 Conventions
  • Report the experimental ratio to two decimals and the whole-number ratio beside it.
  • Give the percent difference from the expected ratio.
4. Teacher’s answer-key line
Answer: ___
📌 Conventions
  • Accept answers within rounding of the atomic weights used.
  • Use the Batch tab to make a whole worksheet answer key.
5. Plain text for chat, forums or a spreadsheet
___
📌 Conventions
  • Write subscripts as plain digits: NH3.

∑ 6. Mole Ratio Formula and Related Equations

The mole ratio formula is nB = nA × (b ÷ a), where a and b are the coefficients of A and B in the balanced equation. The other cards feed into it or use it.

①
Mole-to-Mole Conversion
nB = nA × (b ÷ a)
a, bCoefficients of A and B in the balanced equation
Example6.00 mol H2 × 2/3 = 4.00 mol NH3
②
Moles from What You Measure
n = m ÷ M  ·  solution: n = c × V  ·  gas at STP: n = V ÷ 22.414 L  ·  particles: n = N ÷ NA
Example44.1 g ÷ 44.097 g/mol = 1.000 mol C3H8; 25.0 mL × 0.100 M = 0.00250 mol NaOH
③
Number of Mole Ratios
number of ratios = n(n − 1) ÷ 2 for n substances
ExamplePropane combustion has 4 substances, so 4 × 3 ÷ 2 = 6 mole ratios (12 if each is also written the other way round)
④
Experimental Mole Ratio
ratioi = ni ÷ nsmallest, then × k (k = 1, 2, 3, …) until every value is within 0.1 of a whole number
ExampleFe 0.03581, O 0.05375: 1 : 1.501; × 2 = 2 : 3
⑤
Percent Difference from Expected
% difference = (experimental ratio − expected ratio) ÷ expected ratio × 100
ExampleAg : Cu found 2.004, expected 2: +0.2%
⑥
Molar Ratio of Two Compounds
nA : nB = (mA ÷ MA) : (mB ÷ MB)  ·  mass of B for ratio a : b: mB = nA × (b ÷ a) × MB
Example10.0 g NaCl (58.440) : 10.0 g KCl (74.548) = 0.1711 : 0.1341 = 1.28 : 1
⑦
DNA Insert : Vector Molar Ratio
insert (ng) = vector (ng) × (insert bp ÷ vector bp) × ratio  ·  MW(dsDNA) = bp × 617.96 + 36.04 g/mol
Example50 ng × (1000 ÷ 3000) × 3 = 50.0 ng insert; 50 ng of a 3000 bp vector is 26.97 fmol
SourceAtomic weights: CIAAW 2024; dsDNA weight per base pair as used in vendor mass-to-moles calculators

🔀 7. How to Calculate Mole Ratio: Flowchart, Step by Step

This flowchart shows how to calculate mole ratios and use them, exactly as the mole ratio calculator does, on the same problem used in the Excel, R, Python and by-hand sections: nitrogen and hydrogen make ammonia. How many moles and grams of NH3 form from 6.00 mol of H2?

Start or result Data step Calculation step Yes or no check
StartN2 + H2 → NH3Given 6.00 mol H2; find NH3
CheckIs the equation balanced?
NoBalance it: N2 + 3H2 → 2NH3.
YesRead the coefficients directly.
1
Read the coefficientsN2 1, H2 3, NH3 2Mole ratio 1 : 3 : 2
CheckIs the given amount in moles?
Yes6.00 mol H2: go on.
NoGrams: divide by the molar mass first.
2
Write the ratio wanted over given2 mol NH3 ÷ 3 mol H2Units of H2 cancel
3
Multiply6.00 mol × 2/34.00 mol NH3
4
Grams, if asked4.00 mol × 17.031 g/mol68.1 g NH3
Result4.00 mol (68.1 g) of NH3 from 6.00 mol of H2NH3 : H2 = 2 : 3 2.00 mol N2 neededEvery amount ÷ its coefficient gives the same 2.00 mol.

Check any box yourself: the Excel sheet in Section 9, the R script in Section 10 and the Python script in Section 11 all return 4.00 mol and 68.1 g of NH3 for this problem.

📝 8. How to Use This Mole Ratio Calculator

  1. Choose what you have. A chemical equation, measured amounts for an experimental ratio, two compounds, or a DNA vector and insert.
  2. Type the equation. Write N2 + H2 -> NH3; it is balanced for you and the balanced form appears under the box.
  3. Pick the substance you have and the one you want. Choose “every other substance” to convert to all of them at once.
  4. Enter the amount and unit. Use mol, mmol, g, mg, kg, mL of solution with molarity, litres of gas at STP or particles; leave it empty to see only the ratios.
  5. For an experimental ratio, enter each substance and its amount. Formulas, names or a molar mass in g/mol all work; add the expected ratio to get the percent difference.
  6. For two compounds, choose ratio or mass. Enter both masses for the molar ratio, or a target ratio to get the mass of B to weigh.
  7. For DNA, enter the vector length and mass and each insert’s length and ratio. Presets give 3 : 1, 2 : 1, 5 : 1 and 1 : 1; add ng/µL to get volumes.
  8. Press the button. Nothing is calculated before you press it, and changing any input clears the old answer.
  9. Read the ratios, the steps and the charts. The Verified badge means mass is conserved and every amount matches the ratio.
  10. Copy, share or batch. Copy the answer, share a link, download a report, or solve a whole worksheet on the Batch tab.

📈 9. How to Calculate Mole Ratio in Excel

Excel handles mole ratio calculations in a few small tables: the coefficients of the balanced equation, a ratio column, a conversion row, an experimental-ratio table with MIN, and a DNA insert row. The sheets use the headline problems, so they must return 4.00 mol NH3, Cu : Ag = 1 : 2 and 50.0 ng of insert, the same as the mole ratio calculator above.

The key cell: with the moles you have in B6, the coefficient you have in C3 and the coefficient you want in C4, =B6*C4/C3 gives the moles you want.

9.1 The functions you need

You wantExcel formulaNote
Moles from grams=B2/C2Mass ÷ molar mass
Mole ratio B per A=C4/C2Coefficient ÷ coefficient
Ratio in lowest terms=C2/GCD(C2,C4)&" : "&C4/GCD(C2,C4)Text such as 1 : 2
Mole-to-mole=B6*C4/C3Have × wanted ÷ given
Grams of product=B7*D4Moles × molar mass
Experimental ratio=D2/MIN(D$2:D$3)Divide by the smallest
DNA insert (ng)=B2*(B4/B3)*B5Vector ng × length ratio × molar ratio
The mass trap. Never divide grams by grams to get a mole ratio. Convert each mass to moles first, or the ratio is a mass ratio.

9.2 Step by step

1 Coefficients and mole ratios

Type each substance with its coefficient from the balanced equation; divide to get each ratio per mole of N2.

Xmole-ratio.xlsx - ExcelD3fx=C3/C$2ACD1SubstanceCoefficientmol per mol N22N2113H2334NH322

N2 : H2 : NH3 = 1 : 3 : 2.

2 Mole-to-mole conversion

Multiply the moles you have by the coefficient you want over the coefficient you have.

=B6*C4/C3 =B7*D4
Xmole-ratio.xlsx - ExcelB7fx=B6*C4/C3ABCD2SubstanceCoefM (g/mol)3H2 (have)32.0164NH3 (want)217.03156mol H26.007mol NH34.008g NH368.1

6.00 mol H2 gives 4.00 mol NH3, 68.1 g.

3 Experimental mole ratio

Moles from each mass, then divide by the smallest with an absolute reference.

=B2/C2 =D2/MIN(D$2:D$3)
Xmole-ratio.xlsx - ExcelE3fx=D3/MIN(D$2:D$3)ABCDE1MetalgMmolRatio2Cu1.2763.5460.019991.0003Ag4.32107.8700.040052.004

Cu : Ag = 1 : 2.004, so 1 : 2.

4 DNA insert : vector molar ratio

Vector mass and length, insert length and the molar ratio give the insert mass.

Xmole-ratio.xlsx - ExcelB6fx=B2*(B4/B3)*B5AB2Vector mass (ng)503Vector length (bp)30004Insert length (bp)10005Insert : vector ratio36Insert mass (ng)50.07Vector (fmol)26.97

50 ng of a 3000 bp vector at 3 : 1 needs 50.0 ng of a 1000 bp insert.

9.3 Awkward cases

  • Fractional coefficients (H2 + ½O2): the ratios are the same; multiply all coefficients by 2 if you want whole numbers.
  • Ratios near .5 or .33: add a column =E2*2 or =E2*3 before rounding with ROUND.
  • Several inserts: one row per insert with the same vector cells, referenced with $.

9.4 Why your Excel answer might differ

SituationWhat happensFix
Answer 2.25 times too big or smallRatio upside downWanted on top, given on the bottom
Ratio from an unbalanced equationWrong coefficientsBalance first
Third decimal differsRounded molar masses (N 14, H 1)Use 14.007 and 1.008
DNA mass slightly different from a vendor toolAverage bp weight 617.96, 650 or 660 g/molThe ratio formula cancels it; only fmol differ
ToolMole-to-mole
Excel / Google Sheets=B6*C4/C3
R6.00 * coef["NH3"] / coef["H2"]
Pythonamount * coef[wanted] / coef[given]
Casio fx-991EX6.00 × 2 ÷ 3 =

9.5 Charting in Excel

  1. Next to each substance, compute its moles for your amount: =$B$6*C2/$C$3.
  2. Insert → Clustered Column; the bar heights follow the 1 : 3 : 2 ratio, as in chart 2 above.

9.6 Excel errors you will probably hit

Excel showsWhyFix
#DIV/0!A coefficient or molar mass cell is emptyFill columns C and D
#NUM!GCD was given a decimal coefficientUse whole-number coefficients
#VALUE!A unit typed in a number cell (“6.00 mol”)Numbers only; put units in the header

📈 10. How to Calculate Mole Ratio in R

This base R script stores the coefficients as a named vector, prints every mole ratio with combn, converts 6.00 mol of H2 to ammonia, calculates an experimental Cu : Ag ratio from masses, checks the answers and saves a 300 dpi chart. For the headline problem it prints 4.00 mol and 68.1 g of NH3, matching the mole ratio calculator on this page.

base R nothing to install
Copy the whole block. It runs top to bottom in RStudio or with Rscript mole_ratio.R. Change only the coef, M and mass lines.

10.1 The complete script

R, base only, saves mole_ratio.png

# ============================================================
# Mole ratio calculator in R (base R only):
# all mole ratios from a balanced equation, a mole-to-mole conversion,
# and an experimental mole ratio from measured masses
# StatsUnlock - https://statsunlock.com/mole-ratio-calculator/
# ============================================================

# ---- 1. Balanced equation: N2 + 3 H2 -> 2 NH3 -------------------------------
coef <- c(N2 = 1, H2 = 3, NH3 = 2)
M    <- c(N2 = 28.014, H2 = 2.016, NH3 = 17.031)    # g/mol
gcd  <- function(a, b) if (b == 0) a else gcd(b, a %% b)

# ---- 2. Every mole ratio (all possible pairs) ------------------------------
pairs <- combn(names(coef), 2)
for (k in seq_len(ncol(pairs))) {
  a <- pairs[1, k]; b <- pairs[2, k]; g <- gcd(coef[a], coef[b])
  cat(sprintf("%s : %s = %d : %d\n", a, b, coef[a] / g, coef[b] / g))
}

# ---- 3. Mole-to-mole conversion: 6.00 mol H2 -> NH3 ------------------------
n_wanted <- 6.00 * coef["NH3"] / coef["H2"]          # mol x (2 / 3)
mass_wanted <- n_wanted * M["NH3"]
cat(sprintf("6.00 mol H2 x 2/3 = %.2f mol NH3 = %.1f g\n", n_wanted, mass_wanted))

# ---- 4. Experimental mole ratio: 1.27 g Cu gives 4.32 g Ag -----------------
moles <- c(Cu = 1.27 / 63.546, Ag = 4.32 / 107.870)
ratio <- moles / min(moles)
print(round(ratio, 3))
cat("Whole-number ratio Cu : Ag =", paste(round(ratio), collapse = " : "), "\n")

# ---- 5. Checks -------------------------------------------------------------
stopifnot(round(n_wanted, 2) == 4.00, round(mass_wanted, 1) == 68.1,
          all(round(ratio) == c(1, 2)), abs(ratio["Ag"] - 2.004) < 0.001)
cat("Verdict: Verified (all checks pass)\n")

# ---- 6. Figure: moles of every substance for 6.00 mol H2 -------------------
mol <- 6.00 * coef / coef["H2"]
png("mole_ratio.png", width = 2100, height = 1350, res = 300)
par(mar = c(4, 4.5, 3, 1))
bp <- barplot(mol, col = c("#2563eb", "#ea580c", "#16a34a"), ylab = "mol", ylim = c(0, 7),
              main = "N2 + 3 H2 -> 2 NH3: moles follow the 1 : 3 : 2 ratio")
text(bp, mol + 0.3, sprintf("%.2f mol", mol))
invisible(dev.off())
cat("Saved mole_ratio.png\n")

Output: N2 : H2 = 1 : 3, N2 : NH3 = 1 : 2, H2 : NH3 = 3 : 2, 6.00 mol H2 x 2/3 = 4.00 mol NH3 = 68.1 g, Whole-number ratio Cu : Ag = 1 : 2, Verdict: Verified.

10.2 R traps

  • Index named vectors by name (coef["H2"]) so the ratio cannot be taken from the wrong substance.
  • %% is the remainder operator, used in the gcd function; inside sprintf, a percent sign must also be written %%.
  • Round only when printing; keep full precision for the ratio.

10.3 What each part does

PartWhat it does
combn(names(coef), 2)Every pair: all possible mole ratios
coef[a] / gRatio in lowest terms
6.00 * coef["NH3"] / coef["H2"]Mole-to-mole conversion
moles / min(moles)Experimental mole ratio
stopifnot(...)The checks

10.4 The figure

The script saves mole_ratio.png at 2100 × 1350 pixels and 300 dpi: the moles of N2, H2 and NH3 for 6.00 mol of H2, following the 1 : 3 : 2 ratio.

🐍 11. How to Calculate Mole Ratio in Python

This script does the same in plain Python: a dictionary of coefficients, every mole ratio with itertools.combinations, the mole-to-mole conversion, the experimental ratio, exact checks with fractions.Fraction and a 300 dpi chart. It is the same method the mole ratio calculator runs in your browser.

matplotlib for the chart only

Install once: pip install matplotlib

11.1 The complete script

Python, saves mole_ratio.png

# ============================================================
# Mole ratio calculator in Python:
# all mole ratios from a balanced equation, a mole-to-mole conversion,
# and an experimental mole ratio from measured masses
# StatsUnlock - https://statsunlock.com/mole-ratio-calculator/
# pip install matplotlib
# ============================================================
from fractions import Fraction
from itertools import combinations
from math import gcd
import matplotlib
matplotlib.use("Agg")
import matplotlib.pyplot as plt

# ---- 1. Balanced equation: N2 + 3 H2 -> 2 NH3 -------------------------------
coef = {"N2": 1, "H2": 3, "NH3": 2}
M = {"N2": 28.014, "H2": 2.016, "NH3": 17.031}          # g/mol

# ---- 2. Every mole ratio (all possible pairs) ------------------------------
for a, b in combinations(coef, 2):
    g = gcd(coef[a], coef[b])
    print(f"{a} : {b} = {coef[a] // g} : {coef[b] // g}")

# ---- 3. Mole-to-mole conversion: 6.00 mol H2 -> NH3 ------------------------
given, amount, wanted = "H2", 6.00, "NH3"
n_wanted = amount * coef[wanted] / coef[given]             # mol x (2 / 3)
mass_wanted = n_wanted * M[wanted]
print(f"{amount:.2f} mol {given} x {coef[wanted]}/{coef[given]} = {n_wanted:.2f} mol {wanted} = {mass_wanted:.1f} g")

# ---- 4. Experimental mole ratio: 1.27 g Cu gives 4.32 g Ag -----------------
masses = {"Cu": 1.27, "Ag": 4.32}
molar = {"Cu": 63.546, "Ag": 107.870}
moles = {k: masses[k] / molar[k] for k in masses}
smallest = min(moles.values())
ratio = {k: v / smallest for k, v in moles.items()}
whole = {k: round(v) for k, v in ratio.items()}
print("Experimental:", {k: round(v, 3) for k, v in ratio.items()}, "->", whole)

# ---- 5. Checks ------------------------------------------------------------
assert Fraction(coef["NH3"], coef["H2"]) == Fraction(2, 3)
assert round(n_wanted, 2) == 4.00 and round(mass_wanted, 1) == 68.1
assert whole == {"Cu": 1, "Ag": 2} and abs(ratio["Ag"] - 2.004) < 0.001
print("Verdict: Verified (all checks pass)")

# ---- 6. Figure: moles of every substance for 6.00 mol H2 -------------------
names = list(coef)
mol = [amount * coef[s] / coef[given] for s in names]
fig, ax = plt.subplots(figsize=(7, 4.5))
ax.bar(names, mol, color=["#2563eb", "#ea580c", "#16a34a"])
for i, v in enumerate(mol):
    ax.text(i, v + 0.1, f"{v:.2f} mol", ha="center")
ax.set_ylabel("mol"); ax.set_title("N2 + 3 H2 -> 2 NH3: moles follow the 1 : 3 : 2 ratio")
fig.tight_layout(); fig.savefig("mole_ratio.png", dpi=300)
print("Saved mole_ratio.png")

Output: N2 : H2 = 1 : 3, 6.00 mol H2 x 2/3 = 4.00 mol NH3 = 68.1 g, Experimental: {'Cu': 1.0, 'Ag': 2.004} -> {'Cu': 1, 'Ag': 2}, Verdict: Verified.

11.2 Python traps

  • Fraction(2, 3) keeps the ratio exact; 2 / 3 is a rounded float.
  • round(1.5) gives 2 and round(2.5) gives 2 (round half to even): check values near .5 by multiplying instead.
  • Use the same molar masses as your textbook if you want to match its third decimal.

11.3 Packages

pip install chempy balances equations with balance_stoichiometry, so the coefficients (and mole ratios) can come from formulas; molmass gives molar masses.

11.4 What each part does

PartWhat it does
combinations(coef, 2)All possible mole ratios
amount * coef[wanted] / coef[given]Mole-to-mole conversion
v / smallestExperimental ratio
assert ...The checks

11.5 The figure

The script saves mole_ratio.png at 300 dpi: the moles of each substance for 6.00 mol of H2.

📋 12. Mole Ratio Tables and Worksheet

12.1 Mole ratios of common reactions

Every equation was balanced, and every ratio read off, by the same engine as the mole ratio calculator above.

Balanced equationAll mole ratiosRatios
N2 + 3 H2 → 2 NH3N2 : H2 = 1 : 3; N2 : NH3 = 1 : 2; H2 : NH3 = 3 : 23
2 H2 + O2 → 2 H2OH2 : O2 = 2 : 1; H2 : H2O = 1 : 1; O2 : H2O = 1 : 23
CH4 + 2 O2 → CO2 + 2 H2OCH4 : O2 = 1 : 2; CH4 : CO2 = 1 : 1; CH4 : H2O = 1 : 2; O2 : CO2 = 2 : 1; O2 : H2O = 1 : 1; CO2 : H2O = 1 : 26
C3H8 + 5 O2 → 3 CO2 + 4 H2OC3H8 : O2 = 1 : 5; C3H8 : CO2 = 1 : 3; C3H8 : H2O = 1 : 4; O2 : CO2 = 5 : 3; O2 : H2O = 5 : 4; CO2 : H2O = 3 : 46
C6H12O6 + 6 O2 → 6 CO2 + 6 H2OC6H12O6 : O2 = 1 : 6; C6H12O6 : CO2 = 1 : 6; C6H12O6 : H2O = 1 : 6; O2 : CO2 = 1 : 1; O2 : H2O = 1 : 1; CO2 : H2O = 1 : 16
Fe2O3 + 3 CO → 2 Fe + 3 CO2Fe2O3 : CO = 1 : 3; Fe2O3 : Fe = 1 : 2; Fe2O3 : CO2 = 1 : 3; CO : Fe = 3 : 2; CO : CO2 = 1 : 1; Fe : CO2 = 2 : 36
4 Al + 3 O2 → 2 Al2O3Al : O2 = 4 : 3; Al : Al2O3 = 2 : 1; O2 : Al2O3 = 3 : 23
2 KClO3 → 2 KCl + 3 O2KClO3 : KCl = 1 : 1; KClO3 : O2 = 2 : 3; KCl : O2 = 2 : 33
Mg + 2 HCl → MgCl2 + H2Mg : HCl = 1 : 2; Mg : MgCl2 = 1 : 1; Mg : H2 = 1 : 1; HCl : MgCl2 = 2 : 1; HCl : H2 = 2 : 1; MgCl2 : H2 = 1 : 16
CaCO3 → CaO + CO2CaCO3 : CaO = 1 : 1; CaCO3 : CO2 = 1 : 1; CaO : CO2 = 1 : 13
2 Na + Cl2 → 2 NaClNa : Cl2 = 2 : 1; Na : NaCl = 1 : 1; Cl2 : NaCl = 1 : 23
Zn + 2 HCl → ZnCl2 + H2Zn : HCl = 1 : 2; Zn : ZnCl2 = 1 : 1; Zn : H2 = 1 : 1; HCl : ZnCl2 = 2 : 1; HCl : H2 = 2 : 1; ZnCl2 : H2 = 1 : 16
2 C2H6 + 7 O2 → 4 CO2 + 6 H2OC2H6 : O2 = 2 : 7; C2H6 : CO2 = 1 : 2; C2H6 : H2O = 1 : 3; O2 : CO2 = 7 : 4; O2 : H2O = 7 : 6; CO2 : H2O = 2 : 36
2 N2O5 → 4 NO2 + O2N2O5 : NO2 = 1 : 2; N2O5 : O2 = 2 : 1; NO2 : O2 = 4 : 13
2 Al + 3 CuSO4 → Al2(SO4)3 + 3 CuAl : CuSO4 = 2 : 3; Al : Al2(SO4)3 = 2 : 1; Al : Cu = 2 : 3; CuSO4 : Al2(SO4)3 = 3 : 1; CuSO4 : Cu = 1 : 1; Al2(SO4)3 : Cu = 1 : 36
H2SO4 + 2 NaOH → Na2SO4 + 2 H2OH2SO4 : NaOH = 1 : 2; H2SO4 : Na2SO4 = 1 : 1; H2SO4 : H2O = 1 : 2; NaOH : Na2SO4 = 2 : 1; NaOH : H2O = 1 : 1; Na2SO4 : H2O = 1 : 26

12.2 Insert mass for common cloning setups

Insert mass = vector mass × (insert bp ÷ vector bp) × insert : vector molar ratio, with 50 ng of vector unless stated.

VectorInsertMolar ratioInsert massInsert moles
3000 bp, 50 ng (27.0 fmol)1000 bp3 : 150.0 ng80.9 fmol
3000 bp, 50 ng (27.0 fmol)1000 bp1 : 116.7 ng27.0 fmol
3000 bp, 50 ng (27.0 fmol)500 bp3 : 125.0 ng80.9 fmol
5000 bp, 50 ng (16.2 fmol)1500 bp3 : 145.0 ng48.5 fmol
5000 bp, 100 ng (32.4 fmol)1500 bp2 : 160.0 ng64.7 fmol
2700 bp, 50 ng (30.0 fmol)750 bp3 : 141.7 ng89.9 fmol
6000 bp, 100 ng (27.0 fmol)2000 bp2 : 166.7 ng53.9 fmol
5400 bp, 100 ng (30.0 fmol)150 bp5 : 113.9 ng149.8 fmol
4000 bp, 50 ng (20.2 fmol)4000 bp1 : 150.0 ng20.2 fmol
10000 bp, 100 ng (16.2 fmol)3000 bp2 : 160.0 ng32.4 fmol

12.3 Mole ratio worksheet with answers

Twenty-five questions in three groups: mole ratios from equations, mole-to-mole and gram conversions, and experimental and DNA molar ratios. Every answer was checked by the mole ratio calculator engine. Cover the last column and try them first.

📄 Download the Mole Ratio Worksheet (PDF)

Free printable mole ratio worksheet with answers.

#QuestionWorkingAnswer
A. Read the mole ratio from the equation
1From N2 + 3 H2 → 2 NH3, what is the mole ratio of N2 to NH3?Coefficients 1 and 21 : 2
2From 2 H2 + O2 → 2 H2O, what is the mole ratio of H2 to O2?Coefficients 2 and 12 : 1
3From CH4 + 2 O2 → CO2 + 2 H2O, what is the mole ratio of CH4 to O2?Coefficients 1 and 21 : 2
4From C6H12O6 + 6 O2 → 6 CO2 + 6 H2O, what is the mole ratio of C6H12O6 to CO2?Coefficients 1 and 61 : 6
5From 4 Al + 3 O2 → 2 Al2O3, what is the mole ratio of Al to Al2O3?Coefficients 4 and 22 : 1
6From 2 KClO3 → 2 KCl + 3 O2, what is the mole ratio of KClO3 to O2?Coefficients 2 and 32 : 3
7From 2 Al + 3 CuSO4 → Al2(SO4)3 + 3 Cu, what is the mole ratio of Al to Cu?Coefficients 2 and 32 : 3
8From H2SO4 + 2 NaOH → Na2SO4 + 2 H2O, what is the mole ratio of H2SO4 to NaOH?Coefficients 1 and 21 : 2
B. Mole-to-mole and gram conversions
9N2 + 3 H2 → 2 NH3: how many moles of NH3 form from 2.50 mol N2?n(NH3) = 2.500 mol N2 × 2 mol NH3 / 1 mol N2 = 5.00 mol NH3; m = 5.000 mol × 17.031 g/mol = 85.2 g5.00 mol NH3 (85.2 g)
102 H2 + O2 → 2 H2O: how many moles of H2 react with 3.0 mol O2?n(H2) = 3.00 mol O2 × 2 mol H2 / 1 mol O2 = 6.0 mol H2; m = 6.00 mol × 2.016 g/mol = 12 g6.0 mol H2 (12 g)
11C3H8 + 5 O2 → 3 CO2 + 4 H2O: how many moles of O2 react with 0.500 mol C3H8?n(O2) = 0.5000 mol C3H8 × 5 mol O2 / 1 mol C3H8 = 2.50 mol O2; m = 2.500 mol × 31.998 g/mol = 80.0 g2.50 mol O2 (80.0 g)
124 Al + 3 O2 → 2 Al2O3: how many moles of Al2O3 form from 4.00 mol Al?n(Al2O3) = 4.000 mol Al × 2 mol Al2O3 / 4 mol Al = 2.00 mol Al2O3; m = 2.000 mol × 101.961 g/mol = 204 g2.00 mol Al2O3 (204 g)
132 KClO3 → 2 KCl + 3 O2: how many moles of O2 form from 2.00 mol KClO3?n(O2) = 2.000 mol KClO3 × 3 mol O2 / 2 mol KClO3 = 3.00 mol O2; m = 3.000 mol × 31.998 g/mol = 96.0 g3.00 mol O2 (96.0 g)
14Fe2O3 + 3 CO → 2 Fe + 3 CO2: how many moles and grams of Fe form from 80.0 g Fe2O3?n = 80.00 g ÷ 159.687 g/mol = 0.5010 mol; n(Fe) = 0.5010 mol Fe2O3 × 2 mol Fe / 1 mol Fe2O3 = 1.00 mol Fe; m = 1.002 mol × 55.845 g/mol = 56.0 g1.00 mol Fe (56.0 g)
15CH4 + 2 O2 → CO2 + 2 H2O: how many moles and grams of H2O form from 8.02 g CH4?n = 8.020 g ÷ 16.043 g/mol = 0.4999 mol; n(H2O) = 0.4999 mol CH4 × 2 mol H2O / 1 mol CH4 = 1.00 mol H2O; m = 0.9998 mol × 18.015 g/mol = 18.0 g1.00 mol H2O (18.0 g)
16Mg + 2 HCl → MgCl2 + H2: how many moles and grams of H2 form from 4.86 g Mg?n = 4.860 g ÷ 24.305 g/mol = 0.2000 mol; n(H2) = 0.2000 mol Mg × 1 mol H2 / 1 mol Mg = 0.200 mol H2; m = 0.2000 mol × 2.016 g/mol = 0.403 g0.200 mol H2 (0.403 g)
17HCl + NaOH → NaCl + H2O: how many moles of HCl react with 20.0 mL of 0.150 M NaOH?n = 0.150 mol/L × 20.0 mL ÷ 1000 = 0.003000 mol; n(HCl) = 0.003000 mol NaOH × 1 mol HCl / 1 mol NaOH = 0.00300 mol HCl; m = 0.003000 mol × 36.458 g/mol = 0.109 g0.00300 mol HCl (0.109 g)
C. Experimental, two-compound and DNA molar ratios
18A sample contains 0.635 g of Cu and 2.16 g of Ag. Find the experimental mole ratio.0.00999 mol Cu : 0.0200 mol Ag = 1.00 : 2.00Cu : Ag = 1 : 2
19A sample contains 0.243 g of Mg and 0.160 g of O. Find the experimental mole ratio.0.0100 mol Mg : 0.0100 mol O = 1.00 : 1.00Mg : O = 1 : 1
20A sample contains 1.12 g of Fe and 0.480 g of O. Find the experimental mole ratio.0.0201 mol Fe : 0.0300 mol O = 1.00 : 1.50Fe : O = 2 : 3
21A sample contains 2.08 g of BaCl2 and 0.360 g of H2O. Find the experimental mole ratio.0.00999 mol BaCl2 : 0.0200 mol H2O = 1.00 : 2.00BaCl2 : H2O = 1 : 2
22A sample contains 0.600 g of C and 0.151 g of H. Find the experimental mole ratio.0.0500 mol C : 0.150 mol H = 1.00 : 3.00C : H = 1 : 3
23What is the molar ratio of 4.00 g NaOH to 3.65 g HCl?0.100 mol : 0.100 molNaOH : HCl = 1 : 1.00
24Ligation: 50 ng of a 4000 bp vector and a 1200 bp insert at 3 : 1. How much insert?50 × (1200 ÷ 4000) × 345.0 ng insert
25In-Fusion at 2 : 1 with 100 ng of a 6000 bp vector and a 900 bp insert. How much insert?100 × (900 ÷ 6000) × 230.0 ng insert

📈 13. Mole Ratio Calculation Examples

Eight examples run through the mole ratio calculator, from ammonia to an In-Fusion cloning reaction. Each figure is drawn from the computed numbers: one bar per substance (or DNA fragment) in moles, so the bar heights are the mole ratio.

1
MOLE TO MOLE

Ammonia from hydrogen

Wanted over given: 2/3.

6.00 mol of hydrogen reacts with nitrogen in excess: N2 + 3H2 → 2NH3.

NH3 : H2 = 2 : 34.00 mol NH368.1 g2.00 mol N2
QuantityValueNote
Balanced equationN2 + 3 H2 → 2 NH3Coefficients = mole ratios
Mole ratio N2 : H21 : 31 mol N2 ↔ 3.000 mol H2
Mole ratio N2 : NH31 : 21 mol N2 ↔ 2.000 mol NH3
Mole ratio H2 : NH33 : 21 mol H2 ↔ 0.6667 mol NH3
Reactant N22.00 mol (56.0 g)needed: × 1/3
Given H26.00 mol (12.1 g)6.00 mol
Product NH34.00 mol (68.1 g)formed: × 2/3
Ammonia from hydrogen: moles of each substanceN₂2.00 mol (1)H₂6.00 mol (3)NH₃4.00 mol (2)
One bar per substance, length = moles; the bar lengths are the mole ratio.

What it means: The coefficients 3 and 2 give the ratio 2 mol NH3 per 3 mol H2, so 6.00 × 2/3 = 4.00 mol of ammonia. The same extent, 2.00 mol, uses 2.00 mol of N2.

How to write it: 6.00 mol H2 × (2 mol NH3 / 3 mol H2) = 4.00 mol NH3

2
ALL RATIOS

Burning propane

Four substances, six mole ratios.

44.1 g of propane burns completely: C3H8 + 5O2 → 3CO2 + 4H2O.

1 : 5 : 3 : 41.000 mol C3H85.00 mol O2132 g CO2
QuantityValueNote
Balanced equationC3H8 + 5 O2 → 3 CO2 + 4 H2OCoefficients = mole ratios
Mole ratio C3H8 : O21 : 51 mol C3H8 ↔ 5.000 mol O2
Mole ratio C3H8 : CO21 : 31 mol C3H8 ↔ 3.000 mol CO2
Mole ratio C3H8 : H2O1 : 41 mol C3H8 ↔ 4.000 mol H2O
Mole ratio O2 : CO25 : 31 mol O2 ↔ 0.6000 mol CO2
Mole ratio O2 : H2O5 : 41 mol O2 ↔ 0.8000 mol H2O
Mole ratio CO2 : H2O3 : 41 mol CO2 ↔ 1.333 mol H2O
Burning propane: moles of each substanceC₃H₈1.00 mol (1)O₂5.00 mol (5)CO₂3.00 mol (3)H₂O4.00 mol (4)
One bar per substance, length = moles; the bar lengths are the mole ratio.

What it means: 44.1 g ÷ 44.097 g/mol = 1.000 mol of propane. Each other substance follows its own ratio: 5.00 mol O2 used, 3.00 mol CO2 and 4.00 mol H2O formed.

How to write it: C3H8 : O2 : CO2 : H2O = 1 : 5 : 3 : 4

3
SOLID IRON

Iron from iron(III) oxide

Two moles of iron per mole of oxide.

2.50 mol of iron(III) oxide is reduced by carbon monoxide: Fe2O3 + 3CO → 2Fe + 3CO2.

Fe : Fe2O3 = 2 : 15.00 mol Fe279 g Fe7.50 mol CO
QuantityValueNote
Balanced equationFe2O3 + 3 CO → 2 Fe + 3 CO2Coefficients = mole ratios
Mole ratio Fe2O3 : CO1 : 31 mol Fe2O3 ↔ 3.000 mol CO
Mole ratio Fe2O3 : Fe1 : 21 mol Fe2O3 ↔ 2.000 mol Fe
Mole ratio Fe2O3 : CO21 : 31 mol Fe2O3 ↔ 3.000 mol CO2
Mole ratio CO : Fe3 : 21 mol CO ↔ 0.6667 mol Fe
Mole ratio CO : CO21 : 11 mol CO ↔ 1.000 mol CO2
Mole ratio Fe : CO22 : 31 mol Fe ↔ 1.500 mol CO2
Iron from iron(III) oxide: moles of each substanceFe₂O₃2.50 mol (1)CO7.50 mol (3)Fe5.00 mol (2)CO₂7.50 mol (3)
One bar per substance, length = moles; the bar lengths are the mole ratio.

What it means: Each Fe2O3 gives two Fe, so 2.50 × 2 = 5.00 mol of iron (279 g); it needs 2.50 × 3 = 7.50 mol of CO.

How to write it: 2.50 mol Fe2O3 × (2 mol Fe / 1 mol Fe2O3) = 5.00 mol Fe

4
EXPERIMENTAL

Copper and silver nitrate

Measured masses, whole-number ratio.

1.27 g of copper wire dissolves in silver nitrate solution and 4.32 g of silver forms.

0.01999 mol Cu0.04005 mol Ag1 : 2.004+0.2%
QuantityValueNote
Moles of Cu0.0200 mol1.27 g ÷ 63.546 g/mol
Moles of Ag0.0400 mol4.32 g ÷ 107.870 g/mol
Ratio ÷ smallest1.000 : 2.004Experimental mole ratio
Simplest whole-number ratio1 : 2rounded
Difference for Ag+0.2%found 2.004 vs expected 2.000
Copper and silver nitrate: moles of each substanceCu0.0200 mol (1)Ag0.0400 mol (2)
One bar per substance, length = moles; the bar lengths are the mole ratio.

What it means: Moles of Cu and Ag are in the ratio 1 : 2.004, which rounds to 1 : 2, the ratio in Cu + 2Ag+ → Cu2+ + 2Ag. A 0.2% difference is excellent agreement.

How to write it: Cu : Ag = 0.01999 : 0.04005 = 1 : 2.00

5
HYDRATE

Water in copper sulfate crystals

The water to salt mole ratio is the x in CuSO4·xH2O.

Heating blue copper sulfate leaves 1.60 g of white anhydrous CuSO4 and drives off 0.90 g of water.

0.01002 mol CuSO40.0500 mol H2O1 : 4.98CuSO4·5H2O
QuantityValueNote
Moles of CuSO40.010 mol1.60 g ÷ 159.602 g/mol
Moles of H2O0.050 mol0.90 g ÷ 18.015 g/mol
Ratio ÷ smallest1.000 : 4.983Experimental mole ratio
Simplest whole-number ratio1 : 5rounded
Water in copper sulfate crystals: moles of each substanceCuSO₄0.0100 mol (1)H₂O0.0500 mol (5)
One bar per substance, length = moles; the bar lengths are the mole ratio.

What it means: 0.0500 ÷ 0.01002 = 4.98, which rounds to 5: the hydrate is CuSO4·5H2O.

How to write it: CuSO4 : H2O = 1 : 4.98 ≈ 1 : 5, so CuSO4·5H2O

6
MULTIPLY FIRST

An iron oxide formula

1 : 1.5 means double, not round.

2.00 g of iron combines with 0.860 g of oxygen.

0.03581 mol Fe0.05375 mol O1 : 1.501Fe2O3
QuantityValueNote
Moles of Fe0.0358 mol2.00 g ÷ 55.845 g/mol
Moles of O0.0538 mol0.860 g ÷ 15.999 g/mol
Ratio ÷ smallest1.000 : 1.501Experimental mole ratio
Simplest whole-number ratio2 : 3after × 2
An iron oxide formula: moles of each substanceFe0.0358 mol (2)O0.0538 mol (3)
One bar per substance, length = moles; the bar lengths are the mole ratio.

What it means: O ÷ Fe = 1.501, halfway between whole numbers, so multiply both by 2: 2 : 3, the formula Fe2O3.

How to write it: Fe : O = 1 : 1.50 = 2 : 3, so Fe2O3

7
TWO COMPOUNDS

Equal masses, different moles

10 g each is not 1 : 1.

A mixture contains 10.0 g of NaCl and 10.0 g of KCl.

0.1711 mol NaCl0.1341 mol KCl1.28 : 1mass ratio 1 : 1
QuantityValueNote
Moles of NaCl0.171 mol10.0 g ÷ 58.440 g/mol
Moles of KCl0.134 mol10.0 g ÷ 74.548 g/mol
Molar ratio NaCl : KCl1.28 : 1= 1 : 0.784
Nearest whole-number ratio5 : 4within 0.1
Mass ratio NaCl : KCl1.00 : 1Compare: the molar mass ratio is 0.7839
Mole fraction of NaCl0.561n(A) ÷ (n(A) + n(B))
Equal masses, different moles: moles of each substanceNaCl0.171 molKCl0.134 mol
One bar per substance, length = moles; the bar lengths are the mole ratio.

What it means: KCl has the larger molar mass (74.548 vs 58.440 g/mol), so the same mass holds fewer moles: the molar ratio NaCl : KCl is 1.28 : 1.

How to write it: NaCl : KCl = 0.1711 : 0.1341 = 1.28 : 1

8
DNA CLONING

In-Fusion with two inserts

2 : 1 for each insert.

100 ng of a 5000 bp linearised vector (50 ng/µL) with a 1500 bp insert (20 ng/µL) and an 800 bp insert, each at 2 : 1.

32.4 fmol vector60.0 ng insert 132.0 ng insert 23.00 µL insert 1
QuantityValueNote
Vector100 ng (32.36 fmol)5000 bp, MW 3.090 × 106 g/mol; 2.00 µL
Insert 1 (1500 bp, 2 : 1)60.00 ng (64.73 fmol)exact 60.00 ng; 3.00 µL at 20 ng/µL
Insert 2 (800 bp, 2 : 1)32.00 ng (64.73 fmol)exact 32.00 ng
Total DNA192.0 ngvector + inserts
In-Fusion with two inserts: moles of each substancevector32.4 fmol (100 ng)insert 164.7 fmol (60.0 ng)insert 264.7 fmol (32.0 ng)
One bar per DNA fragment, length = fmol; the bar lengths are the mole ratio.

What it means: Each insert must hold twice as many molecules as the vector, 64.7 fmol. The shorter insert needs less mass for the same number of molecules.

How to write it: Insert 1 = 100 ng × (1500/5000) × 2 = 60.0 ng; insert 2 = 100 × (800/5000) × 2 = 32.0 ng

✏️ 14. How to Calculate Mole Ratio by Hand

This is the written method examiners expect, on the same problem as Sections 7, 9, 10 and 11: how many moles and grams of NH3 form from 6.00 mol of H2?

14.1 How to calculate mole ratio step by step

  1. Balance the equation. N2 + 3H2 → 2NH3.
  2. Read the coefficients of the two substances: H2 3, NH3 2.
  3. Write the mole ratio as a fraction, wanted over given: 2 mol NH3 ÷ 3 mol H2.
  4. Multiply the moles you have: 6.00 mol H2 × 2/3 = 4.00 mol NH3.
  5. Convert to grams if asked: 4.00 mol × 17.031 g/mol = 68.1 g.
  6. Check: 6.00 ÷ 3 = 4.00 ÷ 2 = 2.00, the same extent of reaction.

14.2 How to calculate mole to mole ratio for every substance

For C3H8 + 5O2 → 3CO2 + 4H2O there are six mole ratios: C3H8 : O2 = 1 : 5, C3H8 : CO2 = 1 : 3, C3H8 : H2O = 1 : 4, O2 : CO2 = 5 : 3, O2 : H2O = 5 : 4 and CO2 : H2O = 3 : 4. With 1.000 mol of propane, multiply by each: 5.00 mol O2, 3.00 mol CO2, 4.00 mol H2O.

14.3 How to calculate molar ratio from molecular weight (grams)

Divide each mass by its molecular weight first. 44.1 g of propane ÷ 44.097 g/mol = 1.000 mol, and 44.1 g of CO2 would be 44.1 ÷ 44.009 = 1.002 mol: equal masses, almost equal moles here only because the molar masses happen to be close.

14.4 How to calculate experimental mole ratio

In the classic copper and silver nitrate experiment, 1.27 g of copper wire gives 4.32 g of silver. Moles: Cu 1.27 ÷ 63.546 = 0.01999 mol; Ag 4.32 ÷ 107.870 = 0.04005 mol. Divide by the smaller: 1 : 2.004, so Cu : Ag = 1 : 2, matching Cu + 2Ag+ → Cu2+ + 2Ag (a 0.2% difference). Load sample 6 in the mole ratio calculator to see every step.

14.5 How to calculate the molar ratio of two compounds

10.0 g of NaCl is 10.0 ÷ 58.440 = 0.1711 mol and 10.0 g of KCl is 10.0 ÷ 74.548 = 0.1341 mol, so NaCl : KCl = 1.28 : 1. To make a 1 : 2 mole ratio of glucose to sucrose with 5.00 g of glucose (180.156 g/mol): 0.02775 mol × 2 = 0.05551 mol of sucrose × 342.30 g/mol = 19.0 g.

14.6 How to calculate molar ratio for DNA cloning

For a ligation with T4 DNA ligase at 3 : 1 insert : vector, 50 ng of a 3000 bp vector and a 1000 bp insert: insert = 50 × (1000 ÷ 3000) × 3 = 50.0 ng. In moles, 50 ng ÷ (3000 × 617.96 + 36.04) g/mol = 26.97 fmol of vector and 80.9 fmol of insert. For In-Fusion (Takara recommends 2 : 1 for each insert) with 100 ng of a 5000 bp vector, a 1500 bp insert needs 100 × (1500 ÷ 5000) × 2 = 60.0 ng. The mole ratio calculator gives the same numbers, plus the volumes to pipette.

14.7 On a scientific calculator

On a Casio fx-991EX or fx-82MS, type the chain at once: 6.00 × 2 ÷ 3 = gives 4; then × 17.031 = gives 68.124.

Keep the unrounded answer (Ans) for the next step. Key names differ between models; check your manual.

14.8 Do it in the lab: the mole ratio of copper to silver

Copper wire in silver nitrate solution

  1. Weigh a clean coil of copper wire (about 1.3 g).
  2. Place it in about 50 mL of 0.5 mol/L silver nitrate solution in a beaker; leave it overnight, covered, away from light.
  3. Shake the silver crystals off the wire, rinse the wire with water then acetone, dry and reweigh it to get the copper used.
  4. Collect the silver by filtration, wash with water and acetone, dry to constant mass and weigh.

Hazards: silver nitrate stains skin and is corrosive to eyes; acetone is highly flammable. Wear eye protection and gloves, keep flames away and follow your school’s risk assessment.

Main errors: silver lost in filtration or washing (ratio too low), silver not fully dry (ratio too high), and copper oxide on the wire.

MeasurementValueWorking
Copper wire before2.416 g
Copper wire after1.142 gCopper used 1.274 g = 0.02005 mol
Filter paper0.952 g
Filter paper + dry silver5.270 gSilver 4.318 g = 0.04003 mol
Mole ratio Ag : Cu1.997 : 10.04003 ÷ 0.02005
Whole-number ratioCu : Ag = 1 : 2Cu + 2Ag+ → Cu2+ + 2Ag
Difference from 2 : 1−0.2%(1.997 − 2) ÷ 2 × 100

Example data. A ratio of 1 : 1 would point to copper(I), Cu + Ag+ → Cu+ + Ag; the measured 1 : 2.00 shows copper is oxidised to Cu2+.

14.9 How to calculate mole ratios: practice problems with answers

Ten practice problems, easy to hard. Open each one to see the answer.

1. In 2SO2 + O2 → 2SO3, what is the mole ratio of SO2 to O2?

2 SO2 + O2 → 2 SO3; SO2 : O2 = 2 : 1; SO2 : SO3 = 1 : 1; O2 : SO3 = 1 : 2. Answer: SO2 : O2 = 2 : 1

2. How many moles of O2 are needed to burn 3.00 mol of CH4?

n = 3.00 mol; n(O2) = 3.000 mol CH4 × 2 mol O2 / 1 mol CH4 = 6.00 mol O2; m = 6.000 mol × 31.998 g/mol = 192 g. Answer: 6.00 mol O2 (192 g)

3. How many moles of NH3 form from 1.40 mol of N2?

n = 1.40 mol; n(NH3) = 1.400 mol N2 × 2 mol NH3 / 1 mol N2 = 2.80 mol NH3; m = 2.800 mol × 17.031 g/mol = 47.7 g. Answer: 2.80 mol NH3 (47.7 g)

4. What mass of O2 forms when 24.5 g of KClO3 decomposes?

n = 24.50 g ÷ 122.545 g/mol = 0.1999 mol; n(O2) = 0.1999 mol KClO3 × 3 mol O2 / 2 mol KClO3 = 0.300 mol O2; m = 0.2999 mol × 31.998 g/mol = 9.60 g. Answer: 0.300 mol O2 (9.60 g)

5. How many moles of H2 form when 13.08 g of zinc reacts with HCl?

n = 13.080 g ÷ 65.380 g/mol = 0.20006 mol; n(H2) = 0.20006 mol Zn × 1 mol H2 / 1 mol Zn = 0.2001 mol H2; m = 0.20006 mol × 2.016 g/mol = 0.4033 g. Answer: 0.2001 mol H2 (0.4033 g)

6. 0.486 g Mg burns to give MgO containing 0.320 g O. Find the mole ratio Mg : O.

n = 0.4860 g ÷ 24.305 g/mol = 0.02000 mol; n = 0.3200 g ÷ 15.999 g/mol = 0.02000 mol; Mg: 0.019996 ÷ 0.019996 = 1.000; O: 0.020001 ÷ 0.019996 = 1.000; Mg : O = 1 : 1. Answer: Mg : O = 1 : 1

7. A hydrate of MgSO4 loses 6.30 g of water from 6.00 g of anhydrous salt. Find x in MgSO4·xH2O.

n = 6.000 g ÷ 120.361 g/mol = 0.04985 mol; n = 6.300 g ÷ 18.015 g/mol = 0.3497 mol; MgSO4: 0.049850 ÷ 0.049850 = 1.000; H2O: 0.34971 ÷ 0.049850 = 7.015; MgSO4 : H2O = 1 : 7. Answer: MgSO4 : H2O = 1 : 7

8. What is the molar ratio of 5.00 g CaCO3 to 5.00 g MgCO3?

n = 5.000 g ÷ 100.086 g/mol = 0.04996 mol; n = 5.000 g ÷ 84.313 g/mol = 0.05930 mol; n(CaCO3) : n(MgCO3) = 0.04996 : 0.05930 = 0.8424 : 1 = 1 : 1.187; CaCO3 : MgCO3 ≈ 5 : 6. Answer: CaCO3 : MgCO3 = 1 : 1.19

9. How much 500 bp insert is needed with 50 ng of a 3000 bp vector at 3 : 1?

MW = 3000 bp × 617.96 + 36.04 = 1853916 g/mol; n = 50 ng ÷ MW = 26.97 fmol; m = 50 ng × (500 bp ÷ 3000 bp) × 3 = 25.00 ng. Answer: 25.0 ng insert

10. How many fmol is 100 ng of a 5000 bp plasmid?

MW = 5000 bp × 617.96 + 36.04 = 3089836 g/mol; n = 100 ng ÷ MW = 32.36 fmol; m = 100 ng × (1000 bp ÷ 5000 bp) × 1 = 20.00 ng. Answer: 32.4 fmol

📄 Download the Mole Ratio Worksheet (PDF)

Want more practice on paper? Print the worksheet and check your answers.

14.10 Mistakes that lose marks

Research on stoichiometry finds that most errors come from the mole ratio and the conversion to moles, not the arithmetic (Gulacar et al., 2013; Mulford & Robinson, 2002).

  • Using an unbalanced equation.
  • Taking the ratio from subscripts instead of coefficients.
  • Putting the ratio upside down (given over wanted).
  • Multiplying grams by the mole ratio instead of moles.
  • Rounding an experimental 1 : 1.5 to 1 : 2 instead of doubling it to 2 : 3.
  • Using equal nanograms of insert and vector instead of a molar ratio.
  • Rounding intermediate answers too early.

✅ 15. When Should You Use a Mole Ratio Calculator?

Use it when:
  • You need to convert moles (or grams) of one substance to another through a balanced equation.
  • You want every mole ratio in an equation at once, for example to set up a stoichiometry table.
  • You measured masses in a lab and need the experimental mole ratio or a hydrate formula.
  • You are setting up a ligation, In-Fusion or HiFi assembly and need the insert mass for a molar ratio; the mole ratio calculator works as a DNA molar ratio calculator too.
It cannot tell you:
  • What the products of a reaction are: you must supply the equation.
  • How much product you will actually get (use the theoretical yield calculator for the limiting reagent and percent yield).
  • The best molar ratio for your cloning reaction: vendor ratios are starting points to optimise.
  • Whether a measured ratio is wrong because of a side reaction.

Four real examples

SituationDataResult
Haber process homework6.00 mol H2 with N2 in excess4.00 mol NH3, 68.1 g
Copper and silver nitrate practical1.27 g Cu, 4.32 g AgCu : Ag = 1 : 2.00
Hydrate analysis1.60 g CuSO4, 0.90 g water lostCuSO4·5H2O
Plasmid cloning50 ng 3000 bp vector, 1000 bp insert, 3 : 150.0 ng insert

Decision tree

  1. Do you have a chemical equation? Yes: equation mode, with or without an amount.
  2. Did you measure masses of substances that reacted or formed? Yes: experimental mode.
  3. Do you want the molar ratio of two compounds, or how much of one to weigh for a target ratio? Yes: two-compound mode.
  4. Is it DNA? Yes: DNA mode with the vector and insert lengths.

🔧 16. Mole Ratio Calculator Troubleshooting

“More than one independent way to balance it”

Cause: the equation is really two reactions, or a product is missing. Fix: split it, or type the coefficients yourself as written in your textbook.

The “I have” list is empty

Cause: the arrow is missing or a formula has a typo. Fix: write -> between the sides; the balanced equation appears under the box when it is read.

My mole ratio is upside down

Cause: the given and wanted substances are swapped. Fix: pick the substance you know in “I have” and the one you want in “Find”.

The experimental ratio will not round to whole numbers

Cause: a mass is off, the product is wet, or the reaction was incomplete. Fix: check the masses; the chart shows how far each value is from a whole number.

A name is not recognised

Cause: the name is not in the built-in list. Fix: type the formula, pick one of the suggestions, or type the molar mass in g/mol.

My textbook answer is slightly different

Cause: rounded atomic weights (N 14, H 1). Fix: the ratio itself is exact; only the grams change in the third figure.

The DNA mass differs from NEB or Takara’s calculator

Cause: rounding, or the end correction. Fix: both use mass × length ratio × molar ratio; the exact column includes the 36.04 g/mol end correction.

The insert is longer than the vector

Cause: a large insert in a small backbone. Fix: many protocols then use 1 : 1, or swap the roles so the larger piece is the “vector”.

The solution option asks for molarity

Cause: moles of a solution = molarity × volume. Fix: type the volume in mL and the molarity in mol/L.

⚖️ 17. Assumptions and Limitations of the Mole Ratio Calculator

AssumptionWhat it requiresHow to checkIf it fails
Correct equationThe real reactants and productsYour textbook or the questionCorrect ratios for the wrong reaction
Complete reactionFor conversions, the reaction goes as writtenLimiting reagent, yieldReal amounts are lower
Pure substancesThe masses entered are pure compoundsLabel purity, hydratesCorrect the mass for purity
Ideal gas at STP0 °C and 1 atm, 22.414 L/molUse moles for other conditionsGas moles off by a few percent
Average DNA composition617.96 g/mol per bp, linear double-stranded DNASequence-specific weightfmol off by well under 1%

Limitations. A mole ratio calculator gives stoichiometric ratios; it does not decide which reactant runs out first (use the limiting reagent) or how much product you will isolate (percent yield). Experimental ratios are rounded to whole numbers when every value is within 0.1 of one; a ratio that will not round is a sign of a measurement problem, not a new law of chemistry. DNA molar ratios recommended by vendors are starting points for optimisation, not guarantees.

🎯 18. Conclusion

Your result: ___ . Solve a problem above to add your own summary here.

What the answer is

A mole ratio is the ratio of coefficients in a balanced equation. For N2 + 3H2 → 2NH3 it is 1 : 3 : 2, so 6.00 mol of H2 gives 4.00 mol (68.1 g) of NH3.

What it means chemically

It is the particle ratio of the reaction scaled up to moles, and the bridge between any two substances in every stoichiometric calculation.

Watch out for

Balance first, use coefficients not subscripts, convert grams to moles, put the wanted substance on top, and double an experimental 1 : 1.5 rather than rounding it.

Next steps

Practise with the worksheet in Section 12.3 and the ten problems in Section 14.9, then use the mole ratio calculator for your next stoichiometry problem or cloning reaction.

❓ 19. Frequently Asked Questions

What is a mole ratio calculator?

A mole ratio calculator finds the mole ratios between substances in a balanced chemical equation and uses them to convert moles or grams of one substance into another. This one also calculates experimental mole ratios from lab masses, the molar ratio of two compounds, and DNA insert : vector molar ratios for cloning.

How do you calculate mole ratio?

Balance the equation and take the coefficients of the two substances. In N2 + 3H2 → 2NH3, the mole ratio of H2 to NH3 is 3 : 2. Write it as a fraction to convert between them.

How do you calculate mole to mole ratio?

Multiply the moles you have by the coefficient of the substance you want divided by the coefficient of the substance you have: 6.00 mol H2 × 2/3 = 4.00 mol NH3.

How do you calculate molar ratio from molecular weight?

Divide each mass by its molecular weight to get moles, then divide the moles. 10.0 g of NaCl (58.440 g/mol) is 0.1711 mol and 10.0 g of KCl (74.548 g/mol) is 0.1341 mol, so the molar ratio is 1.28 : 1.

How do you calculate the molar ratio of two compounds?

Convert both amounts to moles and divide one by the other. To make a target ratio instead, multiply the moles of A by the ratio to get the moles of B, then by B’s molar mass to get the mass to weigh.

How do you calculate experimental mole ratio?

Convert each measured mass to moles, divide by the smallest, and round to whole numbers (multiplying first if a value ends near .5 or .33). 1.27 g Cu and 4.32 g Ag give 0.01999 : 0.04005 = 1 : 2.00.

How do you calculate molar ratio from moles?

Divide the moles of one substance by the moles of the other: 0.0500 mol of water and 0.0100 mol of CuSO4 give a 5 : 1 ratio of water to salt.

What are all the possible mole ratios in an equation?

One for each pair of substances: n(n − 1) ÷ 2 for n substances. C3H8 + 5O2 → 3CO2 + 4H2O has six: 1 : 5, 1 : 3, 1 : 4, 5 : 3, 5 : 4 and 3 : 4 (twelve if each is also written the other way round).

Why are mole ratios central to stoichiometric calculations?

Because a balanced equation counts particles, and moles count particles. The mole ratio is the only link between the amount of one substance and another, so every stoichiometry calculation passes through it: grams to moles, mole ratio, moles to grams.

Explain the significance of the mole ratio in stoichiometric calculations.

The mole ratio converts moles of a known substance into moles of an unknown one. It is fixed by the balanced equation and works at any scale, so it lets you predict how much reactant is needed, how much product forms, and which reactant is limiting.

How are mole ratios used in chemical calculations?

As conversion factors: in mole-to-mole and mass-to-mass stoichiometry, limiting reagent problems, theoretical yield, titration calculations (moles of acid per mole of base) and in deriving empirical and hydrate formulas from experimental data.

Is the mole ratio the same as the mass ratio?

No. The mole ratio N2 : H2 is 1 : 3, but the mass ratio is 28.014 : 6.048, about 4.6 : 1. They are equal only when the molar masses are equal.

How do you calculate molar ratio for DNA cloning?

Insert mass (ng) = vector mass (ng) × (insert length ÷ vector length) × the insert : vector molar ratio. 50 ng of a 3000 bp vector with a 1000 bp insert at 3 : 1 needs 50.0 ng of insert.

What molar ratio should I use for ligation (NEB)?

A 3 : 1 insert : vector molar ratio is the usual starting point for T4 DNA ligase cloning, with 1 : 1 to 7 : 1 worth testing. For NEBuilder HiFi assembly, NEB’s guidelines suggest 2 : 1 for a single insert, more for small fragments, and 1 : 1 for multi-fragment assemblies of similar size.

What is the In-Fusion molar ratio (Takara)?

Takara recommends a 2 : 1 insert : vector molar ratio for In-Fusion cloning, including 2 : 1 for each insert in multiple-insert reactions (2 : 2 : 1 for two inserts), 3–5 : 1 for 150–350 bp fragments, and 5–15 : 1 for short oligos.

How do you convert ng of DNA to pmol or fmol?

Divide the mass by the molecular weight, bp × 617.96 + 36.04 g/mol for double-stranded DNA. 50 ng of a 3000 bp plasmid is 50 × 10−9 g ÷ 1.854 × 106 g/mol = 26.97 fmol.

How do you calculate mole ratios with grams?

Convert the grams to moles first (grams ÷ molar mass), apply the mole ratio, and convert back with the other molar mass if you need grams: 44.1 g propane ÷ 44.097 = 1.000 mol × 3 = 3.00 mol CO2 × 44.009 = 132 g.

Can a mole ratio be a fraction or a decimal?

Yes. 2 : 1 and 1 : 0.5 are the same ratio. Equations are written with whole numbers by convention, but experimental mole ratios are measured as decimals and then rounded.

How do you calculate mole ratios in Excel, Python or R?

Put the coefficients in cells and divide: =B6*C4/C3 in Excel, amount * coef[wanted] / coef[given] in Python, 6.00 * coef["NH3"] / coef["H2"] in R. Sections 9 to 11 give complete sheets and scripts.

Where can I find mole ratio practice problems with answers?

Section 12.3 has a 25-question mole ratio worksheet with answers, from reading ratios off equations to experimental and DNA molar ratios, and Section 14.9 has ten practice problems with worked answers.

📑 20. Cite This Tool

APA 7th edition
StatsUnlock Team. (2026). Mole ratio calculator [Interactive chemistry tool]. StatsUnlock. https://statsunlock.com/mole-ratio-calculator/
BibTeX
@misc{statsunlock_moleratio_2026, title={Mole Ratio Calculator}, author={{StatsUnlock Team}}, year={2026}, note={Interactive chemistry tool}, url={https://statsunlock.com/mole-ratio-calculator/}}
Methods wording
Mole ratios were calculated with the StatsUnlock Mole Ratio Calculator (2026) from balanced equations and measured amounts, using CIAAW 2024 standard atomic weights.

🔗 21. Related Tools

📖 22. Glossary of Mole Ratio Terms

TermPlain-English meaning
Avogadro constant6.022 140 76 × 1023 particles per mole.
Balanced equationAn equation with the same number of each atom on both sides.
CoefficientThe number in front of a formula; it gives the mole ratio.
Empirical formulaThe simplest whole-number mole ratio of atoms in a compound.
Experimental mole ratioA mole ratio worked out from measured amounts.
Extent of reactionMoles of any substance ÷ its coefficient; the same for every substance.
fmolFemtomole, 10−15 mol, the usual unit for DNA in cloning.
HydrateA salt with water molecules in its crystals, such as CuSO4·5H2O.
InsertThe DNA fragment being cloned into a vector.
Limiting reagentThe reactant that runs out first; found with mole ratios.
Mass ratioThe ratio of masses; not the same as the mole ratio.
Molar massMass of one mole of a substance, in g/mol (molecular weight).
Molar ratioAnother name for the mole ratio.
MoleThe SI unit of amount of substance.
Mole fractionMoles of one component ÷ total moles.
Mole ratioThe ratio of the amounts in moles of two substances in a reaction.
Mole-to-mole conversionMoles of one substance × mole ratio = moles of another.
StoichiometryThe arithmetic of amounts in chemical reactions.
SubscriptThe small number in a formula; never used for the mole ratio between substances.
VectorThe plasmid or other DNA that carries the insert.

📚 23. References

Peer-reviewed sources for the methods and data used in this mole ratio calculator: standard atomic weights, the definition of the mole, and research on how students learn stoichiometry and mole ratios. Cloning ratios follow the vendors’ published guidelines (New England Biolabs and Takara Bio).

  1. Chandrasegaran, A. L., Treagust, D. F., Waldrip, B. G., & Chandrasegaran, A. (2009). Students’ dilemmas in reaction stoichiometry problem solving: Deducing the limiting reagent in chemical reactions. Chemistry Education Research and Practice, 10(1), 14–23. https://doi.org/10.1039/B901456J
  2. Dori, Y. J., & Hameiri, M. (2003). Multidimensional analysis system for quantitative chemistry problems: Symbol, macro, micro, and process aspects. Journal of Research in Science Teaching, 40(3), 278–302. https://doi.org/10.1002/tea.10077
  3. Furió, C., Azcona, R., & Guisasola, J. (2002). The learning and teaching of the concepts ‘amount of substance’ and ‘mole’: A review of the literature. Chemistry Education Research and Practice, 3(3), 277–292. https://doi.org/10.1039/B2RP90023H
  4. Gabel, D. L., & Sherwood, R. D. (1984). Analyzing difficulties with mole-concept tasks by using familiar analog tasks. Journal of Research in Science Teaching, 21(8), 843–851. https://doi.org/10.1002/tea.3660210806
  5. Güttler, B., Bettin, H., Brown, R. J. C., Davis, R. S., Mester, Z., Milton, M. J. T., ... Stock, M. (2019). Amount of substance – the Avogadro constant and the SI unit “mole”. Metrologia, 56(4), 044002. https://doi.org/10.1088/1681-7575/ab1fae
  6. Gulacar, O., Overton, T. L., Bowman, C. R., & Fynewever, H. (2013). A novel code system for revealing sources of students’ difficulties with stoichiometry. Chemistry Education Research and Practice, 14(4), 507–515. https://doi.org/10.1039/C3RP00029J
  7. Krishnan, S. R., & Howe, A. C. (1994). The mole concept: Developing an instrument to assess conceptual understanding. Journal of Chemical Education, 71(8), 653–655. https://doi.org/10.1021/ed071p653
  8. Marquardt, R., Meija, J., Mester, Z., Towns, M., Weir, R., Davis, R., & Stohner, J. (2018). Definition of the mole (IUPAC Recommendation 2017). Pure and Applied Chemistry, 90(1), 175–180. https://doi.org/10.1515/pac-2017-0106
  9. Meija, J., Coplen, T. B., Berglund, M., Brand, W. A., De Bièvre, P., Gröning, M., ... Prohaska, T. (2016). Atomic weights of the elements 2013 (IUPAC Technical Report). Pure and Applied Chemistry, 88(3), 265–291. https://doi.org/10.1515/pac-2015-0305
  10. Mulford, D. R., & Robinson, W. R. (2002). An inventory for alternate conceptions among first-semester general chemistry students. Journal of Chemical Education, 79(6), 739. https://doi.org/10.1021/ed079p739
  11. Nakhleh, M. B. (1992). Why some students don’t learn chemistry: Chemical misconceptions. Journal of Chemical Education, 69(3), 191–196. https://doi.org/10.1021/ed069p191
  12. Nurrenbern, S. C., & Pickering, M. (1987). Concept learning versus problem solving: Is there a difference? Journal of Chemical Education, 64(6), 508–510. https://doi.org/10.1021/ed064p508
  13. Olmsted, J. (1999). Amounts tables as a diagnostic tool for flawed stoichiometric reasoning. Journal of Chemical Education, 76(1), 52. https://doi.org/10.1021/ed076p52
  14. Pekdağ, B., & Azizoğlu, N. (2013). Semantic mistakes and didactic difficulties in teaching the “amount of substance” concept: A useful model. Chemistry Education Research and Practice, 14(1), 117–129. https://doi.org/10.1039/C2RP20132A
  15. Prohaska, T., Irrgeher, J., Benefield, J., Böhlke, J. K., Chesson, L. A., Coplen, T. B., ... Zhu, X. (2022). Standard atomic weights of the elements 2021 (IUPAC Technical Report). Pure and Applied Chemistry, 94(5), 573–600. https://doi.org/10.1515/pac-2019-0603
  16. Sanger, M. J. (2005). Evaluating students’ conceptual understanding of balanced equations and stoichiometric ratios using a particulate drawing. Journal of Chemical Education, 82(1), 131–134. https://doi.org/10.1021/ed082p131
  17. Schmidt, H.-J., & Jignéus, C. (2003). Students’ strategies in solving algorithmic stoichiometry problems. Chemistry Education Research and Practice, 4(3), 305–317. https://doi.org/10.1039/B3RP90018E
  18. Staver, J. R., & Lumpe, A. T. (1995). Two investigations of students’ understanding of the mole concept and its use in problem solving. Journal of Research in Science Teaching, 32(2), 177–193. https://doi.org/10.1002/tea.3660320206
  19. Tiesinga, E., Mohr, P. J., Newell, D. B., & Taylor, B. N. (2021). CODATA recommended values of the fundamental physical constants: 2018. Reviews of Modern Physics, 93(2), 025010. https://doi.org/10.1103/RevModPhys.93.025010
  20. Yarroch, W. L. (1985). Student understanding of chemical equation balancing. Journal of Research in Science Teaching, 22(5), 449–459. https://doi.org/10.1002/tea.3660220507
STATS UNLOCK · statsunlock.com · Mole Ratio Calculator
RELATED ARTICLES

LEAVE A REPLY

Please enter your comment!
Please enter your name here

Most Popular

Statistical Models

Important Plots & Charts

Calculators and Converters